已知\(m+1=2009^2+2010^2\),求\(\sqrt{2m+1}\)

设\(t=2009\),侧\(m+1=t^2+(t+1)^2\),

\(m+1=t^2+t^2+2t+1\)

\(m=2t^2+2t\)

原式\(\sqrt{2m+1}\)

=\(\sqrt{2(2t^2+2t)+1}\)

=\(\sqrt{4t^2+4t+1}\)

=\(\sqrt{(2t+1)^2}\)

=\(2t+1\)

\(t=2009\),求得\(\sqrt{2m+1}=2t+1=2 * 2009 +1=4019 \)

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